Question

I have the code working exactly the way I’d like to, however I don’t want it to skip onto another column. I just want my macro to run inside column C then exit.
I am new to VBA in excel, so please pardon my faults.
Any help would be much appreciated.
Thanks in advance.

    Sub CopyValuetoRange()
'
' CopyValuetoRange Macro

Dim search_range As Range, Block As Range, last_cell As Range
  Dim first_address$
  Set search_range = ActiveSheet.UsedRange
  Set Block = search_range.Find(what:="*", _
    after:=search_range.SpecialCells(xlCellTypeLastCell), _
    LookIn:=xlValues, searchorder:=xlColumns, searchdirection:=xlDown)
  If Block Is Nothing Then Exit Sub

  Set Block = Block.CurrentRegion
  first_address$ = Block.Address
  Do
    Block.Select
    Selection.End(xlDown).Select
    ActiveCell.CurrentRegion.Rows(2).Select
    Range(Selection, Selection.End(xlDown)).Select
    Selection.FormulaR1C1 = "=R[-1]C"

    'MsgBox "Next Block Range"
    Set last_cell = Block.Cells(Block.Rows.Count)
    Set Block = search_range.FindNext(after:=last_cell).CurrentRegion
  Loop Until Block.Address = first_address$ 'ActiveSheet.Range("C26").End(xlDown).Row


End Sub

Here is something I modified from something I found that will essentially do the same thing, however it puts the first cells value into all cells in the range. And this macro actually stays in Column C, since I found recently because it’s not a region, it’s a range.

Is there a way to change the following to add a formula to all cells in the range that points to the first cell in the range?

Sub Macro5()

    Dim Rng As Range
    Dim RngEnd As Range
    Dim rngArea As Range

        Set Rng = Range("C1")
        Set RngEnd = Cells(Rows.Count, Rng.Column).End(xlDown)
        If RngEnd.Row < Rng.Row Then Exit Sub

        Set Rng = Range(Rng, RngEnd)

        On Error GoTo ExitSub
        Set Rng = Rng.SpecialCells(xlCellTypeConstants)

        For Each rngArea In Rng.Areas
            rngArea.Value = rngArea.Cells(Rng.Rows.Count, 1).Value
        Next rngArea


ExitSub:
    ' Macro will exit here if the range is empty.

End Sub

Answer 1

Here’s what I have, it’s not pretty but it works. I added a column on both sides then removed them after the macro went through the entire column:

Sub CopyFirstCellInRangeInOneColumn()
'
' CopyValuetoRange Macro
Dim search_range As Range, Block As Range, last_cell As Range
  Dim first_address$
  ''
    Columns("C:C").Select
    Selection.Insert Shift:=xlToRight, CopyOrigin:=xlFormatFromLeftOrAbove
    Columns("E:E").Select
    Selection.Insert Shift:=xlToRight, CopyOrigin:=xlFormatFromLeftOrAbove
  ''
  Set search_range = ActiveSheet.Range("D:D")
  Set Block = search_range.Find(what:="*", _
    LookIn:=xlValues, searchorder:=xlColumns, searchdirection:=xlDown)

  'Set search_range = ActiveSheet.UsedRange
  'Set Block = search_range.Find(What:="*", _
  '  After:=search_range.SpecialCells(xlCellTypeLastCell), _
  '  LookIn:=xlValues, SearchOrder:=xlColumns, SearchDirection:=xlDown)


  If Block Is Nothing Then Exit Sub

  Set Block = Block.CurrentRegion
  first_address$ = Block.Address
  Do
    Block.Select
    Selection.End(xlDown).Select
    ActiveCell.CurrentRegion.Rows(2).Select
    Range(Selection, Selection.End(xlDown)).Select
    Selection.FormulaR1C1 = "=R[-1]C"

    MsgBox "Next Block Range"
    Set last_cell = Block.Cells(Block.Rows.Count)
    Set Block = search_range.FindNext(After:=last_cell).CurrentRegion
  Loop Until Block.Address = first_address$ 'ActiveSheet.Range("C26").End(xlDown).Row

    Columns("C:C").Select
    Selection.Delete Shift:=xlToLeft
    Columns("D:D").Select
    Selection.Delete Shift:=xlToLeft


End Sub