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Home/ Questions/Q 6223949
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T08:34:53+00:00 2026-05-24T08:34:53+00:00

I have the current function: function getDaysBetween($start, $end) { $start = strtotime($start); $end =

  • 0

I have the current function:

function getDaysBetween($start, $end) {
    $start = strtotime($start);
    $end = strtotime($end);
    $dateDiff = abs($end- $start);
    $daysBetween = floor($dateDiff/(60*60*24));
    return $daysBetween;
}

The function above does return the days between.

So, for example, August 3 at 3.00 AM minus August 2 at 11PM gives 0.

In this case I would like it to return 1, since these are different days. How can I achieve that?

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  1. Editorial Team
    Editorial Team
    2026-05-24T08:34:53+00:00Added an answer on May 24, 2026 at 8:34 am

    Instead of

    $start = strtotime($start);
    $end = strtotime($end);
    

    use

    $start = strtotime('00:00:00', strtotime($start));
    $end = strtotime('00:00:00', strtotime($end));
    
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