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Home/ Questions/Q 7569355
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Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T15:08:41+00:00 2026-05-30T15:08:41+00:00

I have the following ajax success function. How can I act on the result

  • 0

I have the following ajax success function. How can I act on the result with jquery before appending it? The following code is my attempt, however, the second console statement never writes.

See the current .filter line. I base that as my latest attempt after reading and trying the different methods from here: Use Jquery Selectors on $.AJAX loaded HTML?

$(function ()
{
    $('#myactionlink').click(function (result)
    {
        $.ajax(this.href, {
            success: function (result)
            {
                console.log((new Date()).getTime() + ' - ' + 'result returned.');
                $(result).filter('input[name="RowId"]').each(function (i)
                {
                    var x = (i + 1).toString();
                    console.log((new Date()).getTime() + ' - ' + 'RowId: ' + x);
                    $(this).val(x);
                });
                $('#mypartial').append(result);
            }
        });
        return false;
    });
});

Html Partial being returned.

<div>
    <input id="RowId" name="RowId" type="text" value="">
</div>

Current Inprogress Solution

$(function ()
{
    $('#myactionlink').click(function (result)
    {
        $.ajax(this.href, {
            success: function (result)
            {
                console.log((new Date()).getTime() + ' - ' + 'result returned.');
                var outResult = $(result);
                outResult.filter('[name="RowId"]').each(function (i)
                {
                    var x = (i + 1).toString();
                    console.log((new Date()).getTime() + ' - ' + 'RowId: ' + x);
                    $(this).val(x);
                }).end().appendTo('#mypartial');
            }
        });
        return false;
    });
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T15:08:42+00:00Added an answer on May 30, 2026 at 3:08 pm

    Store a reference to result, modify it, then append it.

    var outResult = $(result);
    outResult.find('[name="RowId"]').each(...).end().appendTo("#mypartial");
    

    You were actually appending the original html and not doing anything with the one you created using $(result).

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