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Asked: 2026-05-26T10:05:05+00:00

I have the following array: array = [{email=>test@test.com, name=>Test}, {email=>testA@test.com, name=>Test A}, {name=>Test B,

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I have the following array: 

 array = [{"email"=>"test@test.com", "name"=>"Test"},
          {"email"=>"testA@test.com", "name"=>"Test A"},
          {"name"=>"Test B", "email"=>"testB@test.com"},
          {"email"=>"testC@test.com", "name"=>"Test C"},
          {"name"=>"Test D", "email"=>"testD@test.com"},
          {"email"=>"testE@test.com"},
          {"name"=>"Test F", "email"=>"testF@test.com"}]

I have a list of “blacklist” emails, for instance:

 blacklist = ["testC@test.com"]

I want to do something like this: 

 array - blacklist 
 # => should remove element {"email"=>"testC@test.com", "name"=>"Test C"}

Surely there is a sexy-Ruby way to do this with .select or something, but I haven’t been able to figure it out. I tried this to no avail:

 array.select {|k,v| v != "testC@test.com"} # => returns array without any changes
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1 Answer

  1. Editorial Team

    I think you’re looking for this:

    filtered_array = array.reject { |h| blacklist.include? h['email'] }

    or if you want to use select instead of reject (perhaps you don’t want to hurt anyone’s feelings):

    filtered_array = array.select { |h| !blacklist.include? h['email'] }

    Your

    array.select {|k,v| ...

    attempt won’t work because array hands the Enumerable blocks a single element and that element will be a Hash in this case, the |k,v| trick would work if array had two element arrays as elements though.

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