Question

I have the following array defined in JavaScript,

var myPriceList = [0, 0, 0, 1, 5, 3]

I need to sort the numbers in an ascending order AND so that 0s show at the end of the sort, like so –

var myPriceList = [1, 3, 5, 0, 0, 0]

I understand I can write a custom function like the one below but I’m just not sure how to incorporate the exception for “0”.

function sortNumber(a,b)
{
  return b - a;
}

Answer 1

function numSort(a,b){
    if(a == 0)
        return 1;
    if(b == 0)
        return -1;
    return a - b;
}

If numSort(a,b) returns a value >0, then the index of a should be higher (and thus later in the sequence). If the value is <0, then b should be later in the sequence. 0 means both are equal in terms or order.

JSFiddle Demo. See also MDN sort reference.