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Home/ Questions/Q 6615591
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T20:28:53+00:00 2026-05-25T20:28:53+00:00

I have the following big array: var divs = [ {class:’A’, top:0, left:0}, {class:’B’,

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I have the following big array:

var divs = [
    {class:'A', top:0,   left:0},
    {class:'B', top:50,  left:60},
    {class:'C', top:30,  left:10},
    {class:'D', top:100, left:180},
    {class:'E', top:80,  left:50},
    {class:'F', top:100, left:200},
    {class:'G', top:50,  left:80}
];

I’d like to isolate just the top values. I tried using split() but I might not be using it correctly because nothing returns as expected.

Once the top values are isolated into their own smaller array I want to iterate over it and find the frequency of occurrence for each value.

Can I please get some help?

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  1. Editorial Team
    Editorial Team
    2026-05-25T20:28:53+00:00Added an answer on May 25, 2026 at 8:28 pm
    var divs = [
                {class:'A', top:0,   left:0},
                {class:'B', top:50,  left:60},
                {class:'C', top:30,  left:10},
                {class:'D', top:100, left:180},
                {class:'E', top:80,  left:50},
                {class:'F', top:100,  left:200},
                {class:'G', top:50,  left:80}
    ];
    var topsy = {};
    for(var i = 0, max = divs.length; i < max; i++){
        var a = divs[i];
        topsy[a.top] = (topsy[a.top] + 1) || 1;
    }
    

    At this point, you will have a topsy that has all of the tops in there, with the key being the top, and the value being the number of times it was in there. To get a list of the keys, you say:

    Object.keys(topsy);
    

    Object.keys doesn’t work in IE.
    You will end up with topsy =

    {
        0: 1,
        30: 1,
        50: 2,
        80: 1,
        100: 2
    }
    

    Then you can say

    Object.keys(topsy);//[3,30,50,80,100]
    

    You got your analysis and array done at one time.

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