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Home/ Questions/Q 6682093
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:39:56+00:00 2026-05-26T04:39:56+00:00

I have the following C++ code snippet: class T { }; void f(const T**)

  • 0

I have the following C++ code snippet:

class T { };

void f(const T**) { }

int main() {
    T *x = new T[5];
    f(&x);
}

When I try to compile, g++ reports invalid conversion from 'T**' to 'const T**'. I have done some research and I understand this error. The typical fix is to change the definition of f(const T**) to f(const T* const*) which immediately fixes the problem.

Unfortunately, in my case, f is a function in another library and I cannot change the definition of f. How can I pass the address of x to f?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:39:57+00:00Added an answer on May 26, 2026 at 4:39 am

    Instead you can pass the address of a pointer storing the same value as x.

    int main() {
        T *x = new T[5];
        T const *y = x;
        f(&y);
    }
    

    When f returns you can copy the value back into x.

    You can also cast the address. A write through T const * to an object of type T * is not an aliasing violation.

    int main() {
        T *x = new T[5];
        f(const_cast<T const**>(&x));
    }
    

    The fact that this is valid is less obvious that simply passing a copy and then assigning back to x in my opinion, anyway.

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