I have the following C code which works:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <malloc.h>
int pw = sizeof(char*); // width of pointer (to char)
int num;
int first = 1;
int size = 0;
int incr = 10;
char *(*arr)[]; // pointer to array of pointers to char */
test(char* s, int i)
{
int j;
char *(*newarr)[]; // pointer to array of pointers to char
if (first) { // first time
arr = malloc(pw*incr); // malloc array
first = 0; // skip from now on
size = incr; // save the size
}
if (i >= size) { // out of space
newarr = malloc(pw*(size+incr)); // get incr bigger space
for (j=0; j<size; j++) // copy the elements from the old
(*newarr)[j] = (*arr)[j]; // array to new array
free(arr); // free the old array space
arr = newarr; // point old array to new array
size = size+incr;
};
int len = strlen(s); // length of s
(*arr)[i] = malloc(len+1); // assign pointer to pointer array element
strcpy((*arr)[i], s); // copy s to array
// both arguments must be pointers
printf("%d\t%s\n", i, (*arr)[i]);
};
main()
{
char* s = "this is a string";
for (num=0; num<30; num++) // add 30 pointers to s to *arr
test(s, num);
for (num=0; num<30; num++)
printf("%d\t%s\n", num, (*arr)[num]); // print out what they point to
};
It prints out ‘i\tthis is a string’ for ‘i’ from 0 to 29 twice. What I want to do is pass ‘arr’ from the top of the file as an argument of ‘test’. The reason I want to do that is because I want to pass several different arrays all of which are declared the same way. If I make the minimal changes to do that I get:
0 this is a string
Segmentation fault (core dumped)
Here is the output of the diff command which shows the minimal changes:
13c13
< char *(*arr)[]; // pointer to array of pointers to char */
---
> char *(*jarr)[]; // pointer to array of pointers to char */
15c15
< test(char* s, int i)
---
> test(char* s, int i, char *(*arr)[])
52c52
< test(s, num);
---
> test(s, num, jarr);
54,55d53
< for (num=0; num<30; num++)
< printf("%d\t%s\n", num, (*arr)[num]); // print out what they point to
In other words everything is the same except for renaming ‘arr’ as ‘jarr’ and passing it to ‘test’.
Thanks in advance,
Mike
The trouble occurs when you call:
You are passing
jarrby value. Inside the function, you are reallocating (the hard way — why not userealloc()which does the copying for you?) the array, but that change does not affect the value ofjarr‘inmain()‘ because it was passed by value. The second time through the loop, you are still passing a null pointer to the function, but you are then dereferencing that null pointer, which is bad news.How to fix?
Fair question…I’m not sure if the old “well, if I want to get to there, I wouldn’t start from here” gag passes muster.
The ‘simplest’ change is to revise the call:
and then ‘just’ revise the function so that it returns a pointer to an array of character pointers. That is a very esoteric function. My brain’s not awake (insufficient caffeine), so I used an intermediate
typedefto get around the problem of how to write the function declaration and definition:It compiles without warnings; that isn’t a guarantee that it’s correct.
The primary alternative is to pass a pointer to a pointer to an array of char pointers to the function, which is even more esoteric.
However, both of these are ‘starting from here’ solutions. You’d do better, on the whole, to devise a different way of handling things. Pointers to arrays are certainly a part of C, but they are at the outer edges of C and you should generally assume that if your design calls for their use, then your design is probably not the best. You should use a simpler
char **(or, perish the thought,char ***; triple indirection is best avoided too, but that isn’t always possible).