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Home/ Questions/Q 964403
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T01:49:16+00:00 2026-05-16T01:49:16+00:00

I have the following C++ function: void foo() { std::cout << bar << std::endl;

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I have the following C++ function:

void foo() {
    std::cout << "bar" << std::endl;
}

I’m porting this to PHP via SWIG. Everything compiles fine and the extension loads properly. I’m able to call foo() from PHP, but I only see the bar output if I run the PHP script from the command line.

$ php script.php
bar

If I load the script in the browser, nothing appears. Why does it not show bar in this case?

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  1. Editorial Team
    Editorial Team
    2026-05-16T01:49:17+00:00Added an answer on May 16, 2026 at 1:49 am

    You can’t print to stdout directly. This will of course only work if you’re using the CLI SAPI. Use php_printf or any of these:

    //Calls php_output_write
    #define PHPWRITE(str, str_len)
    //Calls php_output_write_unbuffered
    #define PHPWRITE_H(str, str_len)
    //Idem:
    #define PUTC(c)
    #define PUTC_H(c)
    #define PUTS(str)
    #define PUTS_H(str)
    int php_write(void *buf, uint size TSRMLS_DC);
    int php_printf(const char *format, ...);
    int php_output_write(const char *str, size_t len TSRMLS_DC);
    int php_output_write_unbuffered(const char *str, size_t len TSRMLS_DC);
    //see the rest of main/output.c
    
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