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Home/ Questions/Q 144247
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Asked: May 11, 20262026-05-11T08:13:24+00:00 2026-05-11T08:13:24+00:00

I have the following class hierarchy in C++: class Base { virtual void apply()

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I have the following class hierarchy in C++:

class Base {     virtual void apply() = 0; };  class Derived : public Base {     virtual void apply() {         // implementation here that uses derived_specialty     }      virtual void derived_specialty() = 0; };   class Implementation : public Derived {        virtual void derived_specialty() {         // implementation     } }; 

I’d like to guarantee that classes at the level of Implementation don’t supply their own implementation of apply, and that they only implement derived_specialty. Is there any way to guarantee that classes inheriting from Derived will not implement apply, so that the Derived::apply implementation is used? My understanding is that in C++, a method made virtual in the Base class is virtual all the way down the inheritance hierarchy, but if there are any tricks in C++ to accomplish, I’d be interested in hearing about them.

I’m always surprised by the things that are allowed by C++, so I thought it was worth asking. 🙂

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  1. 2026-05-11T08:13:24+00:00Added an answer on May 11, 2026 at 8:13 am

    You can kind of do it by composition:

    class Base {     virtual void apply(); };  class Derived : public Base {      class IImplementation {         virtual void derived_specialty() = 0;     };      IImplementation& m_implementation;      Derived(IImplementation& implementation)         : m_implementation(implementation)     {}      virtual void apply() {         // implementation here that uses m_implementation.derived_specialty     }  };   class Implementation : Derived::IImplementation {        virtual void derived_specialty() {         // implementation     } }; 

    Other classes can still subclass Derived and override the apply method, but your Implementation class is no longer one of these classes.

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