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Home/ Questions/Q 8407261
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T23:18:46+00:00 2026-06-09T23:18:46+00:00

I have the following class / package: package Data::CrawlerThreadPool; use Moose; use MooseX::InsideOut; use

  • 0

I have the following class / package:

package Data::CrawlerThreadPool;
use Moose;
use MooseX::InsideOut;
use MooseX::NonMoose;

extends 'Thread::Pool::Simple';

around BUILDARGS => sub {
      my $orig  = shift;
      my $class = shift;
      return $class->$orig( do  => [\&_do_handle],
                            min => 5,
                            max => 10 );
};

sub _do_handle {
    $| = 1;
    print "In Do handle";
}
1;

in my main script, I call it (for e.g…) like this:

#!/usr/bin/env perl
use strict;
use warnings;
use Data::CrawlerThreadPool;

my $tp = Data::CrawlerThreadPool->new();
my @args = qw(0 0 0 0 0 0 0 0 0);
$tp->add(@args) for (0..10);
$tp->join();

Seems like the BUILDARGS method is called, but the process do handle never being called.
What am I missing here?
Thread::Pool::Simple

thanks,

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  1. Editorial Team
    Editorial Team
    2026-06-09T23:18:47+00:00Added an answer on June 9, 2026 at 11:18 pm

    \&_do_handle is not calling the _do_handle sub – it’s just dereferencing a reference to the sub. This idiom is normally used inside an eval {} in order to check that you really have a subref (or an object with a subref overload) — which I don’t think is what you intended to do here.

    If you are intending to actually call _do_handle, then call it directly:

    around BUILDARGS => sub {
          my $orig  = shift;
          my $class = shift;
          return $class->$orig( do  => [ _do_handle() ],
                                min => 5,
                                max => 10 );
    };
    
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