Question

I have the following classes and method:

public class MyGenericClass<T>
    where T : class
{
}

public class MyClass
{
    public TGen MyMethod<TGen>(TGen myGenClass)
        where TGen : MyGenericClass<T>
        where T : class
    {
        return myGenClass;
    }
}

However, this gives an error because it cannot resolve the symbol T in MyMethod. I would prefer to not have to have MyMethod<TGen, T> since it seems a bit redundant to me. Is this possible?

Answer 1

If you want to be able to use any MyGenericClass implementation for your TGen type, then you will need to create a base class of the MyGenericClass implementation to use (of course, this limits what functionality you will get for your TGen instance.

 public class MyGenericClassBase { }
 public class MyGenericClass<T> : MyGenericClassBase { }
 public class MyClass<TGen> 
      where TGen: MyGenericClassBase
 {
     // Stuff
 }