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Home/ Questions/Q 8385147
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T17:35:46+00:00 2026-06-09T17:35:46+00:00

I have the following classes: public abstract class ClassWithHelper<T extends HelperInterface> { Class<T> helperClass;

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I have the following classes:

public abstract class ClassWithHelper<T extends HelperInterface> {
    Class<T> helperClass;
    protected T helper;
        protected Gson gson = new GsonBuilder().create();

        public void loadHelper(String helperString) throws InstantiationException,        IllegalAccessException {
        if (!Strings.isNullOrEmpty(helperString)) {
            wizard = gson.fromJson(helperString, getHelperClass());
        } else {
            wizard = getHelperClass().newInstance();
        }
    }

    protected abstract Class<T> getHelperClass();
}

public class ImplementingClass extends ClassWithHelper<HelperClass> {

    @Override
    protected Class<HelperClass> getHelperClass() {
        return HelperClass.class;
    }
}    

Now, what is nice is that when I call implementingClass.helperClass, it automatically casts it to HelperClass. However, I am wondering if I really need to write and override getHelperClass. I can’t write helper.getClass (because it might be null), and I know the way I have it written there is a type erasure problem.

However, is there a way for me to rewrite my code to avoid having to state the helperClass in two ways and still have type inference for it?

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  1. Editorial Team
    Editorial Team
    2026-06-09T17:35:47+00:00Added an answer on June 9, 2026 at 5:35 pm

    Try this :

    protected Class<T> getHelperClass() {
        final ParameterizedType parameterizedType = (ParameterizedType) getClass().getGenericSuperclass();
        return (Class<T>) parameterizedType.getActualTypeArguments()[0];
    }
    
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