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Home/ Questions/Q 1041329
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:20:11+00:00 2026-05-16T15:20:11+00:00

I have the following classes. public class B { public A a; public B()

  • 0

I have the following classes.

public class B 
{
    public A a;

    public B()
    {
        a= new A();
        System.out.println("Creating B");
    }
}

and

public class A 
{
    public B b;

    public A()
    {
        b = new B();
        System.out.println("Creating A");
    }

    public static void main(String[] args) 
    {
        A a = new A();
    }
}

As can be clearly seen, there is a circular dependency between the classes. if I try to run class A, I eventually get a StackOverflowError.

If a dependency graph is created, where nodes are classes, then this dependency can be easily identified (at least for graphs with few nodes). Then why does the JVM not identify this, at least at runtime? Instead of a throwing StackOverflowError, JVM can at least give a warning before starting execution.

[Update] Some languages cannot have circular dependencies, because then the source code will not build. For example, see this question and the accepted answer. If circular dependency is a design smell for C# then why is it not for Java? Only because Java can(compile code with circular dependencies)?

[update2] Recently found jCarder. According to the website, it finds potential deadlocks by dynamically instrumenting Java byte codes and looking for cycles in the object graph. Can anyone explain how does the tool find the cycles?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:20:12+00:00Added an answer on May 16, 2026 at 3:20 pm

    The constructor of your class A calls the constructor of class B. The constructor of class B calls the constructor of class A. You have an infinite recursion call, that’s why you end up having a StackOverflowError.

    Java supports having circular dependencies between classes, the problem here is only related to constructors calling each others.

    You can try with something like:

    A a = new A();
    B b = new B();
    
    a.setB(b);
    b.setA(a);
    
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