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Home/ Questions/Q 7987465
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T12:09:24+00:00 2026-06-04T12:09:24+00:00

I have the following classes: public class Base { public int someMethod(){…} } public

  • 0

I have the following classes:

public class Base {
   public int someMethod(){...}
}

public class Derrived extends Base {
   @Override
   public int someMethod(){...}
}

Also I have a method that return the List<Base>

List<Base> method() {
   return fetch();
}

Method fetch() returns List<? extends Base> but actually it holds list of instances of Derrived class

List<? extends Base> fetch() {}

But code that defines method method() will not compile. It requires casting to List<Base>. Why I need cast it if I always can treat to instances of that collection as instances of Base class?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T12:09:26+00:00Added an answer on June 4, 2026 at 12:09 pm

    A List<? extends Base> isn’t the same thing as a List<Base>, in the same way that a bunch of bananas isn’t a fruitbowl.

    Consider:

    List<Derived> x = new ArrayList<Derived>();
    
    // This is valid...
    List<? extends Base> y = x;
    
    // This is what you *want* to be valid
    List<Base> z = y;
    
    z.add(new Base());
    
    // This looks fine at compile-time... but what would you expect it to do?
    Derived d = x.get(0);
    

    It’s one thing to treat all existing elements of a List<Derived> as instances of Base – but you can’t add a Base to a List<Base>, whereas you can add one to a List<Derived>. There not every List<Derived> is List<Base>.

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