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Home/ Questions/Q 9202917
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T23:21:43+00:00 2026-06-17T23:21:43+00:00

I have the following code. And I want to complete the assembly code as

  • 0

I have the following code. And I want to complete the assembly code as indicated below:

int main(void)
{
    int x = 10;

    int i=0;
    label1:


    asm (.....) // code to add here: if i>=x then jump to label2

    printf("%d\n",i);

    i++;
    asm (.....) // code to add here: jump to label 1
    label2:

    printf("out\n");
}

My machine is x86 and the Operating system is Ubuntu 12

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  1. Editorial Team
    Editorial Team
    2026-06-17T23:21:44+00:00Added an answer on June 17, 2026 at 11:21 pm

    First, get yourself a list of x86 op codes, should be easy to find online.

    The asm() function follows this order:

    asm ( "assembly code"
               : output operands                  /* optional */
               : input operands                   /* optional */
               : list of clobbered registers      /* optional */
    );
    

    Second, one major problem you have is you can’t “jump” to a C label, you need to make your label an “assembly” label to be able to jump to it. ex:

    int main()
    {
      asm("jmp .end");    // make a call to jmp there
      printf("Hello ");
      asm(".end:");       //make a "jumpable" label
      printf("World\n");
      return 0;
    }
    

    Output of this program is simply “World” as we jumped over the “Hello “. Here’s the same example but with a comparative jump:

    int main()
    {
        int x = 5, i = 0;
        asm(".start:");
        asm("cmp %0, %1;"   // compare input 1 to 2
            "jge .end;"     // if i >= x, jump to .end
            :               // no output from this code
            : "r" (x), "r" (i));  // input's are var x and i
        printf("Hello ");
        i++;
        asm("jmp .start;");    
        asm(".end:");
        printf("World\n");
        return 0;
    }
    
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