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Home/ Questions/Q 8843811
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:19:38+00:00 2026-06-14T11:19:38+00:00

I have the following code and it does exactly what I need it to

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I have the following code and it does exactly what I need it to do however, the loop takes far too long to run (3 minutes +). I am new to VBA so I am not exactly sure 1) what the best alternative is 2) how to use the proper syntax for that alternative and have my code run flawlessly. Thanks!

Dim i As Integer
For i = 2 To 13000

If Sheets("Sheet1").Range(Cells(i, 3), Cells(i, 3)) = "Police" 
    And Sheets("Sheet1").Range(Cells(i, 14), Cells(i, 14)) = "Bi-wkly Uniform Pay" Then _
Sheets("Sheet1").Range(Cells(i, 3), Cells(i, 3)) = "Police - Uniform"

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:19:39+00:00Added an answer on June 14, 2026 at 11:19 am

    Accessing a sheet within a loop is very slow. A better approach is to copy the data into a Variant, array loop over the array and then copy the results back to the sheet

    Something like this:

    Sub Demo()
        Dim i As Long
        Dim datCol3 As Variant
        Dim datCol14 As Variant
    
        With Sheets("Sheet1")
            ' Copy data into a Variant Array
            datCol3 = .Range(.Cells(1, 3), .Cells(13000, 3)).Formula
            datCol14 = .Range(.Cells(1, 14), .Cells(13000, 14)).Value
            ' Loop over the array
            For i = 2 To 13000
                If datCol3(i, 1) = "Police" And datCol14(i, 1) = "Bi-wkly Uniform Pay" Then
                    datCol3(i, 1) = "Police - Uniform"
                End If
            Next
            'Return the results to the sheet
            .Range(.Cells(1, 3), .Cells(13000, 3)).Formula = datCol3
        End With
    End Sub
    
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