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Home/ Questions/Q 934181
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T20:57:26+00:00 2026-05-15T20:57:26+00:00

I have the following code: #!/bin/bash for f in `find . ! -type d`;

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I have the following code:

#!/bin/bash

for f in `find . ! -type d`;
do
        line=`grep -i 'todo' $f | sed 's/^[ \t]*//'`
        if [ $line ]; then
                echo "$f:"
                echo "$line"
        fi
done

but the condition is not working as I would expect it, I need it to only work if something other than an empty string (or nothing) is returned by the command.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T20:57:27+00:00Added an answer on May 15, 2026 at 8:57 pm

    Some ideas:

    • You need to quote your $f in the grep line to deal with files with spaces in their names.
    • Perhaps you should use -f rather than ! -d, otherwise your find may hang on fifos.
    • For me the \t escape didn’t work as a tab match, it consumed a leading t in a test case file line, so I just inserted a raw tab character in the script instead.
    • Use the double square bracket test otherwise you need an operator in there, or at least some quotes.

    A slight variation on your script would then be:

    find . -type f | while read f
    do
            # raw tab in here ------------------- v
            line=`grep -i 'todo' "$f" | sed 's/^[  ]*//'`
            if [[ $line ]]; then
                    echo "$f:"
                    echo "$line"
            fi
    done
    
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