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Asked: 2026-05-10T19:58:43+00:00

I have the following code block in my xslt; <xsl:when test=StatusData/Status/Temperature > 27> <td

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I have the following code block in my xslt;

      <xsl:when test='StatusData/Status/Temperature > 27'>         <td bgcolor='#ffaaaa'>                         <xsl:value-of select='StatusData/Status/Temperature' />                       </td>       </xsl:when>

But as you might guess when the value is 34,5 instead of 34.5 it is recognised as a string which makes integer comparison not possible. I thought replacing , with . would be solution that needs a char replace. My question is how I can do this or It would be great to know more about string operations in XSLT…

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1 Answer

  1. There is a translate() function in XPath:

    test='translate(StatusData/Status/Temperature, ',', '.') > 27'

    Additionally you should make use of the number function, which converts it’s argument to a number (or NaN, if that fails):

    test='number(translate(StatusData/Status/Temperature, ',', '.')) > 27.0'

    See the documentation for translate() and the documentation for number() at w3.org.

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