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Home/ Questions/Q 7538217
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T07:04:00+00:00 2026-05-30T07:04:00+00:00

I have the following code, but it won’t compile: Class<? extends something>[] classes =

  • 0

I have the following code, but it won’t compile:

Class<? extends something>[] classes = new Class<? extends something>[5]();

Why exactly won’t this work? And is there a way around this? I also tried it with Class<?> and that didn’t work either.

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  1. Editorial Team
    Editorial Team
    2026-05-30T07:04:02+00:00Added an answer on May 30, 2026 at 7:04 am

    The answer has to do with Array Creation Expression.

    The rule clearly states:

    The rules above imply that the element type in an array creation
    expression cannot be a parameterized type, other than an unbounded
    wildcard
    .

    That’s why your above code will never compile. In fact, the following compile-time error message shows (example):

    /**
     * 
     */
    
    
    /**
     * @author The Elite Gentleman
     *
     */
    public class Test {
    
        /**
         * @param args
         */
        public static void main(String[] args) {
            // TODO Auto-generated method stub
            Class<? extends Exception>[] classes = new Class<? extends Exception>[5];
        }
    
    }
    

    Test.java:17: generic array creation

    Solution (that works, if you follow the above rule):

    Class<? >[] classes = new Class<?>[5];
    

    The above line compiles.

    I hope this helps.

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