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Home/ Questions/Q 6553433
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:34:52+00:00 2026-05-25T12:34:52+00:00

I have the following code: class A { private: int x; public: A() {

  • 0

I have the following code:

class A 
{
private:
    int x;
public:
    A()
    {
        x = 90;
    }
    A(A a1, A a2)
    {
        a1.x = 10;
        a2.x = 20;
    }
    int getX()
    {
        return this->x;
    }
};

I know that code might be weird but I don’t understand why a1 and a2 can access private data member x?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:34:53+00:00Added an answer on May 25, 2026 at 12:34 pm

    Good question. The point is that protection in C++ is class level, not object level. So a method being invoked on one object can access private members of any other instance of the same class.

    This makes sense if you see the role of protection being to allow encapsulation to ensure that the writer of a class can build a cohesive class, and not have to protect against external code modifying object contents.

    Another thought as to the real “why?”. Consider how you write almost any copy constructor; you want access to the original’s underlying data structure, not its presented interface.

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