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Home/ Questions/Q 6642497
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:56:14+00:00 2026-05-25T23:56:14+00:00

I have the following code: class Pet { public: virtual string speak() const {

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I have the following code:

class Pet {
public:
  virtual string speak() const { return ""; }
};

class Dog : public Pet {
public:
  string speak() const { return "Bark!"; }
};

int main() {
  Dog ralph;
  Pet* p1 = &ralph;
  Pet& p2 = ralph;
  Pet p3;

  // Late binding for both:
  cout << "p1->speak() = " << p1->speak() <<endl;
  cout << "p2.speak() = " << p2.speak() << endl;

  // Early binding (probably):
  cout << "p3.speak() = " << p3.speak() << endl;
}

I have been asked to determine whether the compiler uses early or late binding for the final function call. I have searched online but have found nothing to help me. Can someone tell me how I would carry out this task?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:56:15+00:00Added an answer on May 25, 2026 at 11:56 pm

    You can look at the disassembly, to see whether it appears to be redirecting through a vtable.

    The clue is whether it calls directly to the address of the function (early binding) or calls a computed address (late binding). The other possibility is that the function is inlined, which you can consider to be early binding.

    Of course the standard doesn’t dictate the implementation details, there may be other possibilities, but that covers “normal” implementations.

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