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Home/ Questions/Q 3310934
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T21:49:03+00:00 2026-05-17T21:49:03+00:00

I have the following code: def countdown(): def countdown1(): print ‘countdown1’ def countdown2(): def

  • 0

I have the following code:

        def countdown():
            def countdown1():
                print 'countdown1'
                def countdown2():
                    def countdown3():
                        takePic()
                    self.pic.set_markup("<span size='54000'>1</span>");
                    print 1
                    t3 = Timer(1.0, countdown3)
                    t3.start()
                self.pic.set_markup("<span size='54000'>2</span>");
                print 2
                t2 = Timer(1.0, countdown2)
                t2.start()
            self.pic.set_markup("<span size='54000'>3</span>");
            print 3
            t1 = Timer(1.0, countdown1)
            t1.start()

        countdown()

It should show a countdown from 3. The number 3 appears, but afterwards nothing happens. help?

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  1. Editorial Team
    Editorial Team
    2026-05-17T21:49:04+00:00Added an answer on May 17, 2026 at 9:49 pm

    Why not just .join() your timer threads after you .start() them, so that the rest of your code waits until the timers are done to continue?

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