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Home/ Questions/Q 8214945
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T11:37:28+00:00 2026-06-07T11:37:28+00:00

I have the following code float square(float val) { return val*val;} boolean isInCircle(final float

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I have the following code

 float square(float val) { return val*val;}
 boolean isInCircle(final float x,final float y) {

        float squareDistance = square(cx - x) + square(cy - y);
        return squareDistance < square(RADIUS);
    }

where RADIUS is a static final float.

Will the java compiler optimize the call square(RADIUS) ?

What happens when this converted to dalvik code for android ? Will it remain optimized ?

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  1. Editorial Team
    Editorial Team
    2026-06-07T11:37:31+00:00Added an answer on June 7, 2026 at 11:37 am

    Optimizations in Java are done (as far as I know) by the HotSpot compiler at runtime (bytecode is optimized when translated to machine code). So the answer is yes and no.

    The transformed code will be equally optimized, but it depends on JVM, what will do with it. According my experience, it is highly dependent on the JVM and probably in its setting (agressivity of the optimizer). I have tried to compare running of SHA1 with loops and without on Windows JVM and Linux one. In one case the code without loops was many times faster, in the second (I think on Linux) there was only a difference about 40% of the time taken…

    So it is a magic, you might give HotSpot good hints to optimize, or configure JVM, but still, it will depend on the current algorithm of JVM…

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