Question

I have the following code for selecting an option from given list and it usually works, but sometimes it fails with NoSuchElement exception on the second if. I was under the impression that if it does not find the element it just goes back to through the loop again. I believe the explanation is pretty simple… Could anyone enlighten me?

    public static void selectFromList(String vList, String vText, IWebDriver driver)
    {
        for (int sec = 0; ; sec++)
        {
            System.Threading.Thread.Sleep(2500);
            if (sec >= 10) Debug.Fail("timeout : " + vList);
            if (driver.FindElement(By.Id(ConfigurationManager.AppSettings[vList])).Displayed) break;
        }
        new SelectElement(driver.FindElement(By.Id(ConfigurationManager.AppSettings[vList]))).SelectByText(vText);
    }

Answer 1

well, I am Java guy, so I will not provide you the code, but rather the algorithm:

• Yours code (I think) should check, if the element is displayed and if not, wait extra 2,5 secs
• The reason it fails is, that sometimes it takes more than first 2,5 secs to display the element. In that case, check for if the element is displayed will throw exception

So, basically you should do some exception handling in the for loop and catch this exception and do nothing. In Java its done by try and catch block. But because I dont know C# you will have to find out how its done in this language