Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I have the following code:
ifstream initFile;
initFile.open("D:\\InitTLM.csv");
if(initFile.is_open())
{
// Process file
}
The file is not opening. The file does exist on the D: drive. Is there a way to find out exactly why this file cannot be found? Like an “errno”?
You should be able to use your OS’s underlying error reporting mechanism to get the reason (because the standard library is built on the OS primitives). The code won’t be portable, but it should get you to the bottom of your issue.
Since you appear to be using Windows, you would use GetLastError to get the raw code and FormatMessage to convert it to a textual description.