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Home/ Questions/Q 6352415
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Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T22:12:05+00:00 2026-05-24T22:12:05+00:00

I have the following code in C++ and I got the compilation error: a.cpp:

  • 0

I have the following code in C++ and I got the compilation error:

a.cpp: In member function `virtual void Derived<T, D>::run(T&)':
a.cpp:13: error: expected primary-expression before "int"
a.cpp:13: error: expected `;' before "int"

Please help me find out what went wrong here. Thanks a lot.

#include <iostream>
template<typename T> struct Base
{
    virtual void run( T& ){}
    virtual ~Base(){}
};

template<typename T, typename D> struct Derived : public Base<T>
{
    virtual void run( T& t )
    {
        D d;
        d.operator()<int>();//nor does d.operator()<T>(); work
    }
};

template<typename T> struct X
{
    template<typename R>  X(const R& r)
    {
       std::cout << "X(R)" << std::endl;
       ptr = new Derived<T,R>(); 
    }

    X():ptr(0)
    { 
        std::cout << "X()" << std::endl; 
    }

    ~X()
    {
        if(ptr) 
        {
            ptr->run(data);
            delete ptr;
        }
        else
        {
            std::cout << "no ptr" << std::endl;
        }
    }

    Base<T>* ptr; 
    T data;
};

struct writer
{
    template<typename T> void operator()()
    { 
        std::cout << "T "<< std::endl;
    }
};

int main()
{
    {
        writer w;
        X<int> xi1((writer()));
    }
    return 0;
};
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T22:12:06+00:00Added an answer on May 24, 2026 at 10:12 pm

    In Derived<>::run(), change

    d.operator()<int>();
    

    to

    d.template operator()<int>();
    

    For further information, see this FAQ:
    What is the ->template, .template and ::template syntax about?

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