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Home/ Questions/Q 561303
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:26:09+00:00 2026-05-13T12:26:09+00:00

I have the following code in my controller after the user posts the form

  • 0

I have the following code in my controller after the user posts the form but if the validation fails (_applicationValidator.Validate), I normally reload the “Edit” view but in this case I want to keep the dialog open and simply show these errors inside the dialog.

Controller Code:

  [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult Update(ApplicationUpdater applicationUpdater_)
    {
        if (_applicationValidator.Validate(applicationUpdater_, ModelState, ValueProvider))
        {
            _repo.UpdateApplication(applicationUpdater_);
            ApplicationsViewModel vm = new ApplicationsViewModel();
            vm.Applications = _repo.GetApplications();
            return View("Index", vm);
        }
        else
        {
            ApplicationViewModel vm = GetApplicationVM();
            return View("Edit", vm);
        }
    }

View Code (jQuery)

 $(".showEditPopup").click(function() {
            $.post("Applications/ShowEdit",
                { recnum: $(this).parents('tr:first').attr("recnum") },
                function(htmlResult) {
                    $("#EditUserControlDiv").remove();
                    $("#container").append(htmlResult);
                    $("#container select[multiple]").asmSelect();
                    $("#EditUserControlDiv").dialog(
                    {
                        height: 675,
                        width: 650,
                        modal: true
                    }
                    );
                }
           );
        });
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:26:09+00:00Added an answer on May 13, 2026 at 12:26 pm

    As said

    But in this case i want to keep the dialop open and simply show these errors inside the dialog

    Ok.

    After openning the dialog, you have to

    • hide previous error message

    …

    open: function(event, ui) {
        $(".error").css("display", "none");
    }
    

    After clicking dialog button, you have to

    • disable JQuery UI
    • Show “loading…” image
    • Send form

    …

    $("#loading").css("display", "block");
    
    panel.dialog("disable");
    
    panel.dialog("option", "disabled", true);
    

    After response is loaded (You can use JSON as response), you have to

    • Check whether it has errors.

    …

    // var response plays the role of JSON response
    
    var response = {
        "errors":[
            {
                "property-name":"name",
                "error":"Name is required"
            },
            {
                "property-name":"age",
                "error":""
            }
        ]
    };
    
    var hasErrors = false;
    
    for(var i = 0; i < response.errors.length; i++) {
        if(response.errors[i].error != "") {
             hasErrors = true;
    
             $("#" + response.errors[i]["property-name"] + "-error")
               .text(response.errors[i]["error"])
               .css("display", "block");
        }
    }
    
    if(!hasErrors) {
        panel.dialog("close");
    
        alert("success form!");
    } else {
        panel.dialog("enable");
    
        panel.dialog("option", "disabled", false);
    }
    

    Here you can see in Action

    Notice you have a default behavior. So you can put it inside a external function

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