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Home/ Questions/Q 7848407
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T18:11:29+00:00 2026-06-02T18:11:29+00:00

I have the following code in my project: int percent = 2; int count

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I have the following code in my project:

  int percent = 2;
  int count = 10;
  int percentagefill = (percent/10)*count; 
  System.out.println(percentagefill);

Basically what is happening is that, I’m setting two variables, percent and count. I then calculate the percentage fill. For some strange reason the percentage fill is resulting in a 0, when in this case it should be 2. Any ideas why? Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-02T18:11:31+00:00Added an answer on June 2, 2026 at 6:11 pm

    intdivided by int will still result in int. In this case:

    (percent/10)*count
    = (2/10)*10
    = (0) * 10 <-- 0.2 is rounded down to 0
    = 0
    

    You can read this question for reference. Also, here’s the Java spec where is says that integer division is rounded towards 0. As for the fix, as long as floating point precision does not become an issue, just use double as PaulP.R.O said.

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