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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T16:05:28+00:00 2026-05-11T16:05:28+00:00

I have the following code in Perl: if (index ($retval, $_[2]) != -1) {

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I have the following code in Perl:

if (index ($retval, $_[2]) != -1) {
    @fs = split ($_[2], $_[1]);

$_[2] is the delimiter variable and $_[1] is the string that the delimiter may exist in. ($_[0] is used elsewhere) You may have guessed that this code is in a subroutine by those variable names.

Anyway, onto my question, when my delimiter is something innocuous like 'a' or ':' the code works like it should. However, when it is something that would get parsed by Perl regex, like a '\' character, then it does not work like it is supposed to. This makes sense because in the split function Perl would see something like:

split (/\/, $_[1]); 

which makes no sense to it at all because it would want this:

split (/\//, $_[1]);

So with all of that in mind my question, that I cannot answer, is this: “How do I make it so that any delimiter that I put into $_[2], or all the ASCII characters, gets treated as the character it is supposed to be and not interpreted as something else?”

Thanks in advance,

Robert

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  1. Editorial Team
    Editorial Team
    2026-05-11T16:05:29+00:00Added an answer on May 11, 2026 at 4:05 pm

    You can use quotemeta to escape $_[2] properly so it will work in the regex without getting mangled. This should do it:

    my $quoted = quotemeta $_[2];
    @fs = split( $quoted, $_[1] );
    

    Alternatively, you can use \Q in your regex to escape it. See “Escape Sequences” in perlre.

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