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Home/ Questions/Q 650917
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T22:06:19+00:00 2026-05-13T22:06:19+00:00

I have the following code in the front end <asp:Content ID=Content1 ContentPlaceHolderID=cphMain runat=server> <script

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I have the following code in the front end

 <asp:Content ID="Content1" ContentPlaceHolderID="cphMain" runat="server">
        <script type="text/javascript">
            //on upload button click temporarily disables ajax to perform upload actions
            function conditionalPostback(sender, args) 
            {
                if (args.EventTarget == '<%= ((Button)frmvwMainDetail.FindControl("bttnRateUploadUpload")).UniqueID %>') {
                    args.EnableAjax = false;
                }
            }
        </script>
    ...
</asp:content>

When the page load, it’ complaining about ((Button)frmvwMainDetail.FindControl(“bttnRateUploadUpload”)).UniqueID is null value. So my question how to put some checking on this ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T22:06:20+00:00Added an answer on May 13, 2026 at 10:06 pm

    use ClientID not UniqueID

    • The control’s UniqueID property is rendered as the name attribute.

    • The control’s ClientID property is rendered as the id attribute.

    Do something with your code OnPageLoad:

    // Define the name and type of the client scripts on the page.
        String csname1 = "PopupScript";
        Type cstype = this.GetType();
    
        // Get a ClientScriptManager reference from the Page class.
        ClientScriptManager cs = Page.ClientScript;
    
        // Check to see if the startup script is already registered.
        if (!cs.IsStartupScriptRegistered(cstype, csname1))
        {
          String cstext1 = "alert('Hello World:"+ bttnRateUploadUpload.ClientID + "');";
          cs.RegisterStartupScript(cstype, csname1, cstext1);
        }
    
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