Question

I have the following code:

#include <iostream>
#include <string>
#include <unistd.h>

using namespace std;

int main()
{
    // Variables
    string sDirectory;

    // Ask the user for a directory to move into
    cout << "Please enter a directory..." << endl;
    cin >> sDirectory;
    cin.get();

    // Navigate to the directory specified by the user
    int chdir(sDirectory);

    return 0;
}

The purpose of this code is pretty self explanatory: to set a user specified directory as the current directory. My plan is to carry out operations on the files contained therein. However, when I attempt to compile this code, I receive the following error

error: cannot convert ‘std::string’ to ‘int’ in initialization

with reference being made to the line reading int chdir(sDirectory). I’ve just started programming and am only now starting to have to find out about platform specific functions, which this one is, so any help on this matter would be most appreciated.

Answer 1

int chdir(sDirectory); isn’t the correct syntax to call the chdir function. It is a declaration of an int called chdir with an invalid string initializer (`sDirectory).

To call the function you just have to do:

chdir(sDirectory.c_str());

Note that chdir takes a const char*, not a std::string so you have to use .c_str().

If you want to preserve the return value you can declare an integer and use a chdir call to initialize it but you have to give the int a name:

int chdir_return_value = chdir(sDirectory.c_str());

Finally, note that in most operating system the current or working directory can only be set for the process itself and any children it creates. It (almost) never affects the process that spawned the process changing its current directory.

If you expect to find the working directory of your shell to be changed once your program terminates you are likely to be disappointed.