Question

I have the following code:

#include <iostream>
using namespace std;

class A
{
    int m_value;
public:
    A(int value)
    {
        m_value = value;
        funcA(&A::param);
    }

    void funcA(void (A::*function)(int))
    {
        (this->*function)(m_value);
    }

    void param(int i)
    {
        cout << "i = " << i << endl;
    }
};


int main()
{
    A ob(10);

    return 0;
}

I have a class in which I call a function that receives another function as parameter. The function call is at line funcA(&A::param). What I want is to be able to pass a function as parameter without being necessary to specify the class scope: funcA(&param). Also I didn’t want to use typedefs that’s why I have the code a little ‘dirty’.

Is there any possibility to achieve this?

Answer 1

This cannot be done. A function pointer in a class must be identified using the class scope (A::function)