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Home/ Questions/Q 5840855
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T11:48:35+00:00 2026-05-22T11:48:35+00:00

I have the following code: #include stdafx.h #include <iostream> #include <conio.h> using namespace std;

  • 0

I have the following code:

#include "stdafx.h"
#include <iostream>
#include <conio.h>
using namespace std;
#define MNAME 30
class Person {
public:
    char name[MNAME + 1];
};
class Student : public Person {
};
class Staff : public Person {
};
class Faculty : public Student, public Staff {
};

int _tmain(int argc, _TCHAR* argv[])
{
    Faculty faculty;
    cout << "Address of faculty.Person::name: " << &faculty.Person::name << endl;
    cout << "Address of faculty.Student::name: " << &faculty.Student::name << endl;
    cout << "Address of faculty.Staff::name: " << &faculty.Staff::name << endl;

    getch();
    return 0;
}

When executed, the program gives the results:

Address of faculty.Person::name: 0012FF20 // **Line 1**
Address of faculty.Student::name: 0012FF20 // **Line 2**
Address of faculty.Staff::name: 0012FF3F // **Line 3**

I don’t get it. Why the address in Line 1 and Line 2 is different from Line 3, while both Student and Staff inherits name from Person?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T11:48:35+00:00Added an answer on May 22, 2026 at 11:48 am

    With regular multiple inheritance you get multiple copies of shared base classes. If you want one copy, use virtual inheritance.

    Explained well in Wikipedia

    class Student : public virtual Person {
    };
    class Staff : public virtual Person {
    };
    

    Will get you what you expected

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