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Home/ Questions/Q 7008311
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:43:06+00:00 2026-05-27T21:43:06+00:00

I have the following code: $ips = file_get_contents($_SERVER[‘DOCUMENT_ROOT’]./visitors.txt); $arr = explode(,,$ips); $today = strtotime(date(‘Y-m-d

  • 0

I have the following code:

$ips = file_get_contents($_SERVER['DOCUMENT_ROOT']."/visitors.txt");
$arr = explode(",",$ips);

$today =  strtotime(date('Y-m-d H:i:s'));

for ($n = 0, $max = count($arr); $n <= $max; $n++) {
$visArr = explode("#",$arr[$n]);
$visDate = strtotime($visArr[1]); //$visArr[1] = 2011-12-27 14:10:45
  if($visDate < $today){
     unset ($arr[$n]);  //remove array item if its date not within 24 hours 
  }
}

The data is stored like this:

xxx.xxx.xxx.xxx#2011-12-27 11:56:24,

xxx.xxx.xxx.xxx#2011-12-28 11:56:24,

I want to get the visitors from the last 24 hours.

I don’t want to use MySQL db, I just want to use the txt file but I’m stuck.

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:43:07+00:00Added an answer on May 27, 2026 at 9:43 pm

    I can see 2 problems:
    1st you are comparing the stored time with current time and saying that it will filter array item if its date not within 24 hours..

    I think you should use $today = strtotime(“-1 day”);
    and name yesterday instead of today..

    Secondly and reason of error is that you are exploding data in file with , which will give you “” ie null for last element in array..and thats why strtotime function is giving error for that value..

    what you should do is:

    if($visArr[1])
    {
        $visDate = strtotime($visArr[1]); //$visArr[1] = 2011-12-27 14:10:45
          if($visDate < $today){
             unset ($arr[$n]);  //remove array item if its date not within 24 hours
          }
    }
    
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