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Home/ Questions/Q 6808281
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:56:10+00:00 2026-05-26T19:56:10+00:00

I have the following code: map<StatTypesEnum, ValueHandler*>::const_iterator itr; for(itr=player1->Stats.begin(); itr!=player1->Stats.end(); itr++) { cout <<

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I have the following code:

map<StatTypesEnum, ValueHandler*>::const_iterator itr;

for(itr=player1->Stats.begin(); itr!=player1->Stats.end(); itr++)
{
    cout << "Stat: " << itr->first << " Value: " << (ValueHandler*)(itr->second)->getValue() << endl;
}

The getValue() method returns an int. If I cout the value outside of the iterator, it displays in base10 decimal, however when i return the value using an iterator (as above) it displays in base16, hex.

Just for completeness, the following line displays as base10:

cout << player1->Stats[Power]->getValue() << endl;

I would like the iterator to display base10.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:56:11+00:00Added an answer on May 26, 2026 at 7:56 pm

    When you print (ValueHandler*)(itr->second)->getValue() you should be getting a hexadecimal value because that’s how pointers are printed. You probably shouldn’t be casting the return value of getValue() to a ValueHandler*. You probably intended to cast itr->second to that pointer type (although it’s not necessary) but just got the parentheses wrong. Here’s what casting itr->second would look like:

    ((ValueHandler*) itr->second)->getValue()
    

    And what you want is probably:

    itr->second->getValue()
    
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