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Home/ Questions/Q 1036351
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T14:41:24+00:00 2026-05-16T14:41:24+00:00

I have the following code: myFunc(); bar(); myFunc() is making an ajax request I

  • 0

I have the following code:

myFunc();
bar();

myFunc() is making an ajax request

I don’t want to execute bar() until myFunc()’s request has completed.

I also do not want to move the call to bar() inside of myFunc.

possible?

EDIT

Here is the code I ended up with:

var FOO = {
 init: function(blah)
 {
  // Callbacks to pass to the AJAX challenge data load
  var callbacks = {
   myFunc1: function(){ myFunc1(blah); },
   myFunc2: function(){ myFunc2(blah); },
  };

  this.bar(callbacks); // Load the challenge data and setup the game
 },
 bar: function(callbacks) { ..loop through and execute them.. }

};
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T14:41:25+00:00Added an answer on May 16, 2026 at 2:41 pm

    In order to do what you are looking for, you must find a way for bar() to communicate with myFunc().

    When you say that you do not want to move the call to bar() inside myFunc() this can be interpreted in several ways.

    For example, you could make bar() a parameter of myFunc()

    function bar() {
       // do what bar() does
    }
    
    function myFunc(callback) {
       // use callback in the onreadystatechange property of the xmlhtprequest object
    }
    
    myFunc(bar)
    

    I hope this will help you

    Jerome Wagner

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