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Home/ Questions/Q 5945515
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T16:41:34+00:00 2026-05-22T16:41:34+00:00

I have the following code: ObjectOutputStream oo = new ObjectOutputStream(new FileOutputStream(test.dat)); ArrayList<String> list =

  • 0

I have the following code:

ObjectOutputStream oo = new ObjectOutputStream(new FileOutputStream("test.dat"));
ArrayList<String> list = null;
for(int i = 0; i < 10; i++)
{
    list = new ArrayList<String>();
    list.add("Object" + i);
    oo.writeObject(list);
}
oo.close();

When I open the test.dat file and unserialize the objects, I get all the objects. But if I change my code to this:

ObjectOutputStream oo = new ObjectOutputStream(new FileOutputStream("test.dat"));
ArrayList<String> list = new ArrayList<String>();
for(int i = 0; i < 10; i++)
{
    list.clear(); //clear the earlier objects
    list.add("Object" + i);
    oo.writeObject(list);
}
oo.close();

Now when I read the objects, I only get the first one i.e. Object0. Can anyone please explain the behavior?

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  1. Editorial Team
    Editorial Team
    2026-05-22T16:41:34+00:00Added an answer on May 22, 2026 at 4:41 pm

    When you write an object to an ObjectOutputStream twice, then the second time will just be written as a reference to the original data (“that ArrayList with id x that I wrote before”).

    This happens even if the content of the object has changed (as it does in your case), therefore you will only have 1 full serialization (the first one) and 9 references to that in the second case.

    You could call ObjectOutputStream.reset() to discard the list of previously written objects and force it to do a full serialization again.

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