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Home/ Questions/Q 6986761
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:51:01+00:00 2026-05-27T18:51:01+00:00

I have the following code: package application; import java.util.Timer; import java.util.TimerTask; public class Application

  • 0

I have the following code:

package application;

import java.util.Timer;
import java.util.TimerTask;

public class Application {

       public String name = "Brad" ;

       public static void main ( String [ ] args ) {
              Timer time = new Timer ( );
              time.schedule ( new TimerTask ( ) {
                     @Override
                     public void run ( ) {
                            System.out.println( "Name: " ) ;
                     }
              }, 0, 10000 );

       }

}

how can I access methods and / or properties of the class within run () function?
honestly, I do not know how I can have access to the context .. and no idea how to pass the object as parameter, as in PHP

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:51:02+00:00Added an answer on May 27, 2026 at 6:51 pm

    You can access instance variables but in your case you can not access name since it is not static. If you want to use field variables, then you need to declare them as final in order to be able to use them inside an anonymous class.

    Example:

    package application; 
    
    import java.util.Timer;
    import java.util.TimerTask;
    
    public class Application {
      public static String name = "Brad" ;
    
      public static void main ( String [ ] args ) {
        final String lastName = "Brad's last name";
    
        Timer time = new Timer ( );
        time.schedule ( new TimerTask ( ) {
          @Override
          public void run ( ) {
            System.out.println( "Name: " + name + " " + lastName ) ;
          }
        }, 0, 10000 );
      }
    }
    
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