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Home/ Questions/Q 1034669
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T14:25:43+00:00 2026-05-16T14:25:43+00:00

I have the following code parts: typedef struct Board* BoardP; typedef struct Board {

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I have the following code parts:

typedef struct Board* BoardP;

typedef struct Board {
    int _rows;
    int _cols;
    char *_board;

} Board;

char* static allocateBoard(BoardP boardP, int row, int col) {

    boardP->_rows = row;
    boardP->_cols = col;
    boardP->_board = malloc(row * col * sizeof(char));

    return boardP->_board;
}

i can’t seem to figure out why it gives the error
expected identifier or ‘(’ before ‘static’
it gives the error after i changed return type to be char*. when it was void no error was given.

and one more question: i was taught that cast is needed when using malloc, however, this seems to be working ok without a cast. is it needed in this case?

thanks

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  1. Editorial Team
    Editorial Team
    2026-05-16T14:25:44+00:00Added an answer on May 16, 2026 at 2:25 pm

    Your function prototype needs to be:

    static char* allocateBoard(BoardP boardP, int row, int col)
    

    No cast is needed on malloc() in C; however, it is in C++.

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