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Home/ Questions/Q 8041807
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T04:20:53+00:00 2026-06-05T04:20:53+00:00

I have the following code: <?php $a = 1; $b = 2; echo sum:

  • 0

I have the following code:

<?php

    $a = 1;
    $b = 2;

    echo "sum: " .  $a + $b;
    echo "sum: " . ($a + $b);

?>

When I execute my code I get:

2
sum: 3

Why does it fail to print the string "sum:" in the first echo? It seems to be fine when the addition is enclosed in parentheses.

Is this weird behaviour anywhere documented?

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  1. Editorial Team
    Editorial Team
    2026-06-05T04:20:56+00:00Added an answer on June 5, 2026 at 4:20 am

    Both operators the addition + operator and the concatenation . operator have the same operator precedence, but since they are left associative they get evaluated like the following:

    echo (("sum:" . $a) + $b);
    echo ("sum:" . ($a + $b));
    

    So your first line does the concatenation first and ends up with:

    "sum: 1" + 2
    

    (Now since this is a numeric context your string gets converted to an integer and thus you end up with 0 + 2, which then gives you the result 2.)

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