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Home/ Questions/Q 6776009
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T15:58:29+00:00 2026-05-26T15:58:29+00:00

I have the following code: <?php $a= 11; echo <select name=’rabboSelect’ style=’width:300px;’>; $sqlQuery=SELECT *

  • 0

I have the following code:

<?php 
        $a= 11;
        echo "<select name='rabboSelect' style='width:300px;'>";
        $sqlQuery="SELECT * FROM writers";
        $result=sql($sqlQuery);
        while($row = mysql_fetch_array($result))
        {
            $a .= "<option value='" .$row["ID"]."'>" . $row["name"] . "<option>";
        }
        echo str_replace("<option></option>", "", $a);;
        echo "</select>";
        ?>

and in the html it’s adding <option></option> after each one, even if I try to delete it:

<select name="rabboSelect" style="width:300px;">11<option value="2">הרב מילר</option><option></option><option value="3">משה דוויד</option><option></option><option value="4">קלמי גריינמן</option><option></option><option value="5">בנימין יעבץ</option><option></option><option value="8">אליהו פרץ</option><option></option></select>

How can I stop this from happening?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T15:58:30+00:00Added an answer on May 26, 2026 at 3:58 pm

    Firstly, I wonder why you are setting $a=11; – did you maybe mean $a='';?

    Next, you are missing a / in the closing option tag. If you tried View Source rather than viewing the DOM, you’d see that rather than the extra options.

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