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Home/ Questions/Q 6329265
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:37:33+00:00 2026-05-24T17:37:33+00:00

I have the following code: <?php mysql_connect(localhost, root, ); mysql_select_db(coockie); $filename =excelreport.xls; $contents =

  • 0

I have the following code:

<?php
    mysql_connect("localhost", "root", "");
    mysql_select_db("coockie");

    $filename ="excelreport.xls";
    $contents = "date \t ip \t visits \t \n";

    $result=mysql_query("select * from test");

    $mydate='';
    $myip='';
    $visits='';

    while($data=mysql_fetch_assoc($result))
    {
        $mydate.=explode(",", $data['date']);
        $myip.=explode(",", $data['ip']);
        $visits.=$data['visits'];

    }

    print_r($mydate);

    //header('Content-type: application/ms-excel');
    //header('Content-Disposition: attachment; filename='.$filename);
    //echo $contents;
?>

$mydate is outputted as string Array. I need it outputted like array of values. Any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-05-24T17:37:34+00:00Added an answer on May 24, 2026 at 5:37 pm

    You are misusing string concatenation operator .=

    $mydate.=explode(",", $data['date']);
    

    explode gives you an array, and with .= it’s converted to string Array. The proper way is to use [] operator

    $mydate=array();
    $myip=array();
    $visits='';
    
    while($data=mysql_fetch_assoc($result))
    {
        $mydate[]=explode(",", $data['date']);
        $myip[]=explode(",", $data['ip']);
        $visits.=$data['visits'];
    
    }
    
    print_r($mydate);
    
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