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Home/ Questions/Q 6844295
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:21:32+00:00 2026-05-27T00:21:32+00:00

I have the following code: <?php $start = 1; $timestart = microtime(1); for ($i

  • 0

I have the following code:

<?php
$start = 1;

$timestart = microtime(1);
for ($i = 0; $i < 1000000; $i++) {
    $result1 = $start * 4;
}
echo "\n";
echo microtime(1) - $timestart;
echo "\n";

$timestart = microtime(1);
for ($i = 0; $i < 1000000; $i++) {
    $result2 = $start << 2;
}
echo "\n";
echo microtime(1) - $timestart;
echo "\n";

This outputs:

0.14027094841003

0.12061500549316

I found on the Internet a Google interview question (which I wanted to apply for a developer, but I realize I can’t), and one of the questions asked what the fastest way was to multiply a number. My first thought was to use the * sign, so I tested it.

My question is, why is shifting bits faster than multiplication?

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:21:33+00:00Added an answer on May 27, 2026 at 12:21 am

    Because bit shifting is something the computer does all the time in hardware, it’s a no-brainer for the CPU. Multiplying arbitrary numbers is something more difficult, because it can’t necessarily be done using simple bit shifting but requires actual work. Multiplying a small integer by 4 happens to be an operation that’s identical to a left-shift by 2. But even if the compiler/runtime/CPU optimizes this operation down to a bit shift, some code first needs to recognize that it can be optimized this way, which is more work than a simple bit shift itself.

    Either way, it’s simply more work because the two operations do entirely different things, even if the outcome of certain operations is the same.

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