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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T09:37:05+00:00 2026-05-14T09:37:05+00:00

I have the following code public class A extends Iterable<Integer> { … public Iterator<Integer>

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I have the following code

public class A extends Iterable<Integer> {
    ...
    public Iterator<Integer> iterator() {
        return new Iterator<Integer>() {

            A a;

            public boolean hasNext() {
                ...
            }

            public Integer next() {
                ...
            }

            public void remove(){
                ...
            } 
};

I would like to initialize the “a” field in the anonymous class with the instance of A that iterator method was called on. Is it possible?

Thank you.

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  1. Editorial Team
    Editorial Team
    2026-05-14T09:37:06+00:00Added an answer on May 14, 2026 at 9:37 am

    You don’t need to.

    You can call methods on the outer class normally within the inner class.
    When you compile it, the compiler will automatically generate a hidden field that contains a reference to the outer class.

    To reference this variable yourself, you can write A.this. (A.this is the compiler-generated field and is equivalent to your a field)

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