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Home/ Questions/Q 8832345
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T08:30:29+00:00 2026-06-14T08:30:29+00:00

I have the following code: public function editAction(Request $request) { $user = $this->get(‘security.context’)->getToken()->getUser(); //

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I have the following code:

public function editAction(Request $request)
{
    $user = $this->get('security.context')->getToken()->getUser();

    // Get the user
    $user2 = $this->getDoctrine()
        ->getRepository('OpinionsUserBundle:User')
        ->findOneById($user->id);

    echo $user->email . '<br>'; // Echo me@example.org
    echo $user2->email . '<br>'; // Echo me@example.org

    $user2->email = 'blah';

    echo $user->email; // Echoes blah
    die();
}

So I know that Doctrine must be doing something with references. The problem is I have a form where the user can change their name and email, but if the email is already in use I want to show an error. However, Symfony binds data to the user object when I check validation, so somehow the session is being updated with the new user object, logging me out or changing my user.

How can I avoid this?

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  1. Editorial Team
    Editorial Team
    2026-06-14T08:30:30+00:00Added an answer on June 14, 2026 at 8:30 am

    The solution I ended up using was refreshing the user model (returning it to it’s original state) if my form validation failed.

    // Reset to default values or else it will get saved to the session
    $em = $this->getDoctrine()->getManager();
    $em->refresh($user);
    
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