Question

I have the following code:

    $RefEquipamento = mysql_real_escape_string($_GET['ID']);
    mysql_select_db($database_connLOOPGEST, $connLOOPGEST);
    $query_rs_equipamento = sprintf("SELECT * FROM  clientes_listaequipamentos WHERE referenciacliente = $RefEquipamento ORDER BY datacriacao_loop DESC LIMIT 1");
    $rs_equipamento = mysql_query($query_rs_equipamento, $connLOOPGEST) or die(mysql_error());
    $row_rs_equipamento = mysql_fetch_assoc($rs_equipamento);
    $totalRows_rs_equipamento = mysql_num_rows($rs_equipamento);

    echo json_encode($row_rs_equipamento);

I’m not an expert in PHP or MySQL, I’m trying to learn something. I’m using Dreamweaver.

The code above works when I pass a number as an argument (for ex. If $RefEquipamento is 200456) this works fine, but when I tried to pass a string (let’s say I’m passing the string “equip1” this doesn’t work, the echo gives me the following message:

“Unknown column ‘equip1’ in ‘where clause'”

Answer 1

try:

$RefEquipamento = “‘” . mysql_real_escape_string($_GET[‘ID’]) . “‘”;
so mysql will handle it as a string.

OR

$query_rs_equipamento = sprintf(“SELECT * FROM clientes_listaequipamentos WHERE referenciacliente = ‘$RefEquipamento’ ORDER BY datacriacao_loop DESC LIMIT 1”);