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Home/ Questions/Q 898339
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T15:01:39+00:00 2026-05-15T15:01:39+00:00

I have the following code (simplified): ostringstream oss; oss << Text ; oss <<

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I have the following code (simplified):

ostringstream oss;

oss << "Text ";

oss << hex << uppercase;
oss.width(8);
oss.fill('0');

oss << var1 << " ";
oss << var2 << " ";

oss << dec << nouppercase;
oss.width(1);

oss << var3 << " another text." << endl;

string result = oss.str();
// work with result...

Where var1, var2 are unsigned int‘s and var3 is an int. The idea is to create a string where var1 and var2 are formated like a hex number (but without the 0x) and var3 as a regular integer. What i found out that only the first number is correctly formated, the second one is not padded with zeroes:

Text 000AF00C 3B7FF 1 another text.

After a while i found out that setting the width and fill parameters AGAIN fixes this. Is there a way how to avoid specifying these formating rules over and over again for each number? The amount of formatted variables is much higher than 2, this was just a simplified example. Wrapping all this into a function is an option, but i would really like to learn how to preserve the formatting with ostringstream.

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  1. Editorial Team
    Editorial Team
    2026-05-15T15:01:40+00:00Added an answer on May 15, 2026 at 3:01 pm

    Sorry some settings for stream formatting are called volatile (has nothing to do with the keyword), you have to set it each time. See here for explanation.

    It will be best to create your own functions.

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