I have the following code that applies a XSLT style
Test.Xml.xslTransform = function(xml, xsl) {
try {
// code for IE
if (window.ActiveXObject) {
ex = xml.transformNode(xsl);
return ex;
}
// code for Mozilla, Firefox, Opera, etc.
else if (document.implementation && document.implementation.createDocument) {
xsltProcessor = new XSLTProcessor();
xsltProcessor.importStylesheet(xsl);
resultDocument = xsltProcessor.transformToFragment(xml, document);
return resultDocument;
}
} catch (exception) {
if (typeof (exception) == "object") {
if (exception.message) {
alert(exception.message);
}
} else {
alert(exception);
}
}
The code is working in IE and firefox but not in Chrome and Safari. Any ideas why?
Update
ResultDocument = xsltProcessor.transformToFragment(xml, document);
The line above is returning null. No error is being thrown.
Update
The code is not working as the xslt file contains xsl:include. Need to find a way to get the include working I will paste progress here
Update
It has been recomended that I use the http://plugins.jquery.com/project/Transform/ plugin. I am trying to use the client side libary as the example of include works here (http://daersystems.com/jquery/transform/).
The code works in IE but still not in chrome.
Test.Xml.xslTransform = function(xml, xsl) {
try {
$("body").append("<div id='test' style='display:none;'></div>");
var a = $("#test").transform({ xmlobj: xml, xslobj: xsl });
return a.html();
}
catch (exception) {
if (typeof (exception) == "object") {
if (exception.message) {
alert(exception.message);
}
} else {
alert(exception);
}
}
}
xml and xsl are both objects being passed in.
Update
I tried changing the XSL file to being something very simple with no include and Chrome is still not applying the stylesheet and IE is. The XSL that is being brought in as an object is:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:rs="urn:schemas-microsoft-com:rowset"
xmlns:z="#RowsetSchema"
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:spsoap="http://schemas.microsoft.com/sharepoint/soap/"
>
<xsl:output method="html"/>
<xsl:template match="/">
<h1>test</h1>
</xsl:template>
</xsl:stylesheet>
Update
The end result that I want is for the xsl to be applied to the xml file. The xsl file has in it includes. I want the trasnfer to happen on the client ideally.
Updated
Rupert could you update the question with the xml and how you’re calling Test.Xml.xslTransform ?
I got the xml using ie8
<?xml version="1.0"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><SearchListItemsResponse xmlns="http://schemas.microsoft.com/sharepoint/soap/"><SearchListItemsResult><listitems xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882" xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882" xmlns:rs="urn:schemas-microsoft-com:rowset" xmlns:z="#RowsetSchema">
<rs:data ItemCount="1">
<z:row ows_Title="Test" ows_FirstName="Test 4" ows_UniqueId="74;#{1A16CF3E-524D-4DEF-BE36-68A964CC24DF}" ows_FSObjType="74;#0" ows_MetaInfo="74;#" ows_ID="74" ows_owshiddenversion="10" ows_Created="2009-12-29 12:21:01" ows_FileRef="74;#Lists/My List Name/74_.000" ReadOnly="False" VerificationRequired="0"/>
</rs:data>
</listitems></SearchListItemsResult></SearchListItemsResponse></soap:Body></soap:Envelope>
The code is being called as follows:
xsl = Test.Xml.loadXMLDoc("/_layouts/xsl/xsl.xslt");
var doc = Test.Xml.xslTransform(xData.responseXML, xsl);
xData is the xml returned by a web service.
If your XSLT is using
xsl:includeyou might receive weird unexplainable errors but always with the same end result: your transformation failing.See this chromium bug report and please support it!
http://code.google.com/p/chromium/issues/detail?id=8441
The bug is actually in webkit though. For more info here’s another link which goes into more detail why it doesn’t work.
The only way around this is to pre-process the stylesheet so that it injects the included stylesheets. Which is what a crossbrowser XSLT library like Sarissa will do for you automatically.
If your looking for jQuery solution:
http://plugins.jquery.com/project/Transform/ is a cross browser XSL plug-in. I’ve succesfully used this to get
xsl:includeworking in the past without much hassle. You don’t have to rewrite your xsl’s this plugin will pre-process them for you. Definitely worth looking at as it’s more lightweight then Sarissa.UPDATE:
This test html page works both in Chrome/FireFox/IE.
input.xml is just a simple xml file containing
<root />transform.xsl is the stripped down xsl you posted.
EDIT
It does however seem the $.transform has problems importing stylesheets from included files:
Here’s how to fix this:
Locate
in
jquery.transform.jsand replace the entire function with this:Now using the previously pasted test index.html use this for
transform.xsl:And this for
include.xslWith the previously posted fix in
jquery.transform.jsthis will now insert the included<h1>Test</h1>on all the browsers.You can see it in action here: http://www.mpdreamz.nl/xsltest