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Home/ Questions/Q 894719
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T14:26:27+00:00 2026-05-15T14:26:27+00:00

I have the following code that I expect to run successfully to completion but

  • 0

I have the following code that I expect to run successfully to completion but the code fails at the line “fail(“this should not be reached”);”. Can someone please explain why the default uncaught exception handler is not called:

public class UncaughtExceptionTest extends TestCase
    implements UncaughtExceptionHandler {

    private final List<Throwable> uncaughtExceptions =
        new CopyOnWriteArrayList<Throwable>();

    class UncaughtExceptionTestInnerClass implements Runnable {
        private final ScheduledThreadPoolExecutor executor =
            new ScheduledThreadPoolExecutor(1);
        private final CountDownLatch latch;

        UncaughtExceptionTestInnerClass(CountDownLatch latch) {
            this.latch = latch;
            executor.schedule(this, 50, TimeUnit.MILLISECONDS);
        }

        @Override
        public void run() {
            System.out.println("This is printed");
            fail("this should fail");
            latch.countDown();
        }
    }

    @Test
    public void testUncaughtExceptions() {
        Thread.setDefaultUncaughtExceptionHandler(this);
        CountDownLatch latch = new CountDownLatch(1);
        UncaughtExceptionTestInnerClass testTheInnerClass =
                new UncaughtExceptionTestInnerClass(latch);
        try {
            if (!latch.await(1, TimeUnit.SECONDS)) {
                if (uncaughtExceptions.size() > 0) {
                    Throwable exception = uncaughtExceptions.get(0);
                    System.out.println("First uncaught exception: " + 
                                    exception.getMessage());
                }
                else {
                    fail("this should not be reached");
                }
            }
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }

    @Override
    public void uncaughtException(Thread t, Throwable e) {
        uncaughtExceptions.add(e);
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T14:26:28+00:00Added an answer on May 15, 2026 at 2:26 pm

    It has to do with the fact you’re using an Executor to run the task. The uncaught exception handler is invoked only if the thread is about to be terminated due to an uncaught exception. If you change your implementation to use a plain thread so that the thread will terminate with the exception, you will see the expected behavior.

    Depending on how you submit tasks, the executor thread may catch all Throwables and handle them. Therefore, the thread does not terminate due to these exceptions, and thus the uncaught exception handler does not get involved. For example, ThreadPoolExecutor.execute(Runnable) will trigger the uncaught exception handler. However, ThreadPoolExecutor.submit(Callable) does not. Also, ScheduledThreadPoolExecutor.schedule() does not either (it has to do with their use of FutureTask for implementation).

    A better way of accessing unexpected exceptions with an executor service is via Future.

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